2(3x^3+2y^2)=

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Solution for 2(3x^3+2y^2)= equation:


Simplifying
2(3x3 + 2y2) = 0
(3x3 * 2 + 2y2 * 2) = 0
(6x3 + 4y2) = 0

Solving
6x3 + 4y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
6x3 + 4y2 + -4y2 = 0 + -4y2

Combine like terms: 4y2 + -4y2 = 0
6x3 + 0 = 0 + -4y2
6x3 = 0 + -4y2
Remove the zero:
6x3 = -4y2

Divide each side by '6'.
x3 = -0.6666666667y2

Simplifying
x3 = -0.6666666667y2

Combine like terms: -0.6666666667y2 + 0.6666666667y2 = 0.0000000000
x3 + 0.6666666667y2 = 0.0000000000

The solution to this equation could not be determined.

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